In the figure, JLN and KLM are straight lines. LJ = LK and ML = MN. If ∠KJL = 56°, find
- ∠JLM
- ∠LMN
(a)
∠JLM
= 56° + 56°
= 112° (Exterior angle of a triangle)
(b)
∠MLN
= 180° - 112°
= 68° (Angles on a straight line)
∠LMN
= 180° - 68° - 68°
= 44° (Isosceles triangle)
Answer(s): (a) 112°; (b) 44°