In the figure, HKM and JKL are straight lines. KH = KJ and LK = LM. If ∠JHK = 57°, find
- ∠HKL
- ∠KLM
(a)
∠HKL
= 57° + 57°
= 114° (Exterior angle of a triangle)
(b)
∠LKM
= 180° - 114°
= 66° (Angles on a straight line)
∠KLM
= 180° - 66° - 66°
= 48° (Isosceles triangle)
Answer(s): (a) 114°; (b) 48°