In the figure, MPR and NPQ are straight lines. PM = PN and QP = QR. If ∠NMP = 51°, find
- ∠MPQ
- ∠PQR
(a)
∠MPQ
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠QPR
= 180° - 102°
= 78° (Angles on a straight line)
∠PQR
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°