In the figure, LNQ and MNP are straight lines. NL = NM and PN = PQ. If ∠MLN = 56°, find
- ∠LNP
- ∠NPQ
(a)
∠LNP
= 56° + 56°
= 112° (Exterior angle of a triangle)
(b)
∠PNQ
= 180° - 112°
= 68° (Angles on a straight line)
∠NPQ
= 180° - 68° - 68°
= 44° (Isosceles triangle)
Answer(s): (a) 112°; (b) 44°