In the figure, JLN and KLM are straight lines. LJ = LK and ML = MN. If ∠KJL = 50°, find
- ∠JLM
- ∠LMN
(a)
∠JLM
= 50° + 50°
= 100° (Exterior angle of a triangle)
(b)
∠MLN
= 180° - 100°
= 80° (Angles on a straight line)
∠LMN
= 180° - 80° - 80°
= 20° (Isosceles triangle)
Answer(s): (a) 100°; (b) 20°