In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 41°, ∠LMK = 34° and ∠GKH = 116°, find
- ∠h
- ∠j
- ∠i
(a)
∠LKM = ∠GKH = 116° (Vertically opposite angles)
∠h
= 180° - 116° - 34°
= 30° (Angles sum of triangle)
(b)
∠j
= 180° - 30°
= 150° (Interior angles)
(c)
∠i
= 180° - 30° - 30° - 34°
= 105° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 105°