In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 50°, ∠VWU = 42° and ∠RUS = 120°, find
- ∠d
- ∠f
- ∠e
(a)
∠VUW = ∠RUS = 120° (Vertically opposite angles)
∠d
= 180° - 120° - 42°
= 18° (Angles sum of triangle)
(b)
∠f
= 180° - 18°
= 162° (Interior angles)
(c)
∠e
= 180° - 18° - 18° - 42°
= 88° (Angles sum of triangle)
Answer(s): (a) 18°; (b) 162°; (c) 88°