In the figure, PQR is parallel to UVW and the line UR cuts ∠QUW into half. Given that RU and QV are straight lines, ∠PQU = 46°, ∠UVT = 34° and ∠QTR = 112°, find
- ∠c
- ∠e
- ∠d
(a)
∠UTV = ∠QTR = 112° (Vertically opposite angles)
∠c
= 180° - 112° - 34°
= 34° (Angles sum of triangle)
(b)
∠e
= 180° - 34°
= 146° (Interior angles)
(c)
∠d
= 180° - 34° - 34° - 34°
= 100° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 146°; (c) 100°