In the figure, BCD is parallel to GHJ and the line GD cuts ∠CGJ into half. Given that DG and CH are straight lines, ∠BCG = 49°, ∠GHF = 36° and ∠CFD = 112°, find
- ∠i
- ∠k
- ∠j
(a)
∠GFH = ∠CFD = 112° (Vertically opposite angles)
∠i
= 180° - 112° - 36°
= 32° (Angles sum of triangle)
(b)
∠k
= 180° - 32°
= 148° (Interior angles)
(c)
∠j
= 180° - 32° - 32° - 36°
= 95° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 95°