In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 42°, ∠WXV = 42° and ∠SVT = 118°, find
- ∠p
- ∠r
- ∠q
(a)
∠WVX = ∠SVT = 118° (Vertically opposite angles)
∠p
= 180° - 118° - 42°
= 20° (Angles sum of triangle)
(b)
∠r
= 180° - 20°
= 160° (Interior angles)
(c)
∠q
= 180° - 20° - 20° - 42°
= 96° (Angles sum of triangle)
Answer(s): (a) 20°; (b) 160°; (c) 96°