In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 44°, ∠VWU = 37° and ∠RUS = 111°, find
- ∠p
- ∠r
- ∠q
(a)
∠VUW = ∠RUS = 111° (Vertically opposite angles)
∠p
= 180° - 111° - 37°
= 32° (Angles sum of triangle)
(b)
∠r
= 180° - 32°
= 148° (Interior angles)
(c)
∠q
= 180° - 32° - 32° - 37°
= 99° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 99°