In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 50°, ∠KLJ = 42° and ∠FJG = 111°, find
- ∠d
- ∠f
- ∠e
(a)
∠KJL = ∠FJG = 111° (Vertically opposite angles)
∠d
= 180° - 111° - 42°
= 27° (Angles sum of triangle)
(b)
∠f
= 180° - 27°
= 153° (Interior angles)
(c)
∠e
= 180° - 27° - 27° - 42°
= 88° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 88°