In the figure, HJK is parallel to NPQ and the line NK cuts ∠JNQ into half. Given that KN and JP are straight lines, ∠HJN = 43°, ∠NPM = 37° and ∠JMK = 111°, find
- ∠e
- ∠g
- ∠f
(a)
∠NMP = ∠JMK = 111° (Vertically opposite angles)
∠e
= 180° - 111° - 37°
= 32° (Angles sum of triangle)
(b)
∠g
= 180° - 32°
= 148° (Interior angles)
(c)
∠f
= 180° - 32° - 32° - 37°
= 100° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 100°