In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 49°, ∠PQN = 35° and ∠KNL = 112°, find
- ∠d
- ∠f
- ∠e
(a)
∠PNQ = ∠KNL = 112° (Vertically opposite angles)
∠d
= 180° - 112° - 35°
= 33° (Angles sum of triangle)
(b)
∠f
= 180° - 33°
= 147° (Interior angles)
(c)
∠e
= 180° - 33° - 33° - 35°
= 96° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 96°