In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 49°, ∠JKH = 35° and ∠EHF = 114°, find
- ∠k
- ∠n
- ∠m
(a)
∠JHK = ∠EHF = 114° (Vertically opposite angles)
∠k
= 180° - 114° - 35°
= 31° (Angles sum of triangle)
(b)
∠n
= 180° - 31°
= 149° (Interior angles)
(c)
∠m
= 180° - 31° - 31° - 35°
= 96° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 96°