In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 41°, ∠KLJ = 39° and ∠FJG = 120°, find
- ∠s
- ∠v
- ∠t
(a)
∠KJL = ∠FJG = 120° (Vertically opposite angles)
∠s
= 180° - 120° - 39°
= 21° (Angles sum of triangle)
(b)
∠v
= 180° - 21°
= 159° (Interior angles)
(c)
∠t
= 180° - 21° - 21° - 39°
= 100° (Angles sum of triangle)
Answer(s): (a) 21°; (b) 159°; (c) 100°