In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 47°, ∠LMK = 33° and ∠GKH = 120°, find
- ∠c
- ∠e
- ∠d
(a)
∠LKM = ∠GKH = 120° (Vertically opposite angles)
∠c
= 180° - 120° - 33°
= 27° (Angles sum of triangle)
(b)
∠e
= 180° - 27°
= 153° (Interior angles)
(c)
∠d
= 180° - 27° - 27° - 33°
= 100° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 100°