In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 49°, ∠STR = 41° and ∠NRP = 113°, find
- ∠c
- ∠e
- ∠d
(a)
∠SRT = ∠NRP = 113° (Vertically opposite angles)
∠c
= 180° - 113° - 41°
= 26° (Angles sum of triangle)
(b)
∠e
= 180° - 26°
= 154° (Interior angles)
(c)
∠d
= 180° - 26° - 26° - 41°
= 90° (Angles sum of triangle)
Answer(s): (a) 26°; (b) 154°; (c) 90°