In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 42°, ∠HJG = 35° and ∠DGE = 112°, find
- ∠b
- ∠d
- ∠c
(a)
∠HGJ = ∠DGE = 112° (Vertically opposite angles)
∠b
= 180° - 112° - 35°
= 33° (Angles sum of triangle)
(b)
∠d
= 180° - 33°
= 147° (Interior angles)
(c)
∠c
= 180° - 33° - 33° - 35°
= 103° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 103°