In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 44°, ∠JKH = 37° and ∠EHF = 116°, find
- ∠b
- ∠d
- ∠c
(a)
∠JHK = ∠EHF = 116° (Vertically opposite angles)
∠b
= 180° - 116° - 37°
= 27° (Angles sum of triangle)
(b)
∠d
= 180° - 27°
= 153° (Interior angles)
(c)
∠c
= 180° - 27° - 27° - 37°
= 99° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 99°