In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 46°, ∠STR = 40° and ∠NRP = 120°, find
- ∠b
- ∠d
- ∠c
(a)
∠SRT = ∠NRP = 120° (Vertically opposite angles)
∠b
= 180° - 120° - 40°
= 20° (Angles sum of triangle)
(b)
∠d
= 180° - 20°
= 160° (Interior angles)
(c)
∠c
= 180° - 20° - 20° - 40°
= 94° (Angles sum of triangle)
Answer(s): (a) 20°; (b) 160°; (c) 94°