In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 44°, ∠KLJ = 35° and ∠FJG = 117°, find
- ∠w
- ∠y
- ∠x
(a)
∠KJL = ∠FJG = 117° (Vertically opposite angles)
∠w
= 180° - 117° - 35°
= 28° (Angles sum of triangle)
(b)
∠y
= 180° - 28°
= 152° (Interior angles)
(c)
∠x
= 180° - 28° - 28° - 35°
= 101° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 101°