In the figure, NPQ is parallel to TUV and the line TQ cuts ∠PTV into half. Given that QT and PU are straight lines, ∠NPT = 48°, ∠TUS = 35° and ∠PSQ = 112°, find
- ∠g
- ∠i
- ∠h
(a)
∠TSU = ∠PSQ = 112° (Vertically opposite angles)
∠g
= 180° - 112° - 35°
= 33° (Angles sum of triangle)
(b)
∠i
= 180° - 33°
= 147° (Interior angles)
(c)
∠h
= 180° - 33° - 33° - 35°
= 97° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 97°