In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 43°, ∠LMK = 41° and ∠GKH = 113°, find
- ∠q
- ∠s
- ∠r
(a)
∠LKM = ∠GKH = 113° (Vertically opposite angles)
∠q
= 180° - 113° - 41°
= 26° (Angles sum of triangle)
(b)
∠s
= 180° - 26°
= 154° (Interior angles)
(c)
∠r
= 180° - 26° - 26° - 41°
= 96° (Angles sum of triangle)
Answer(s): (a) 26°; (b) 154°; (c) 96°