In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 45°, ∠HJG = 38° and ∠DGE = 114°, find
- ∠r
- ∠t
- ∠s
(a)
∠HGJ = ∠DGE = 114° (Vertically opposite angles)
∠r
= 180° - 114° - 38°
= 28° (Angles sum of triangle)
(b)
∠t
= 180° - 28°
= 152° (Interior angles)
(c)
∠s
= 180° - 28° - 28° - 38°
= 97° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 97°