In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 43°, ∠STR = 41° and ∠NRP = 110°, find
- ∠q
- ∠s
- ∠r
(a)
∠SRT = ∠NRP = 110° (Vertically opposite angles)
∠q
= 180° - 110° - 41°
= 29° (Angles sum of triangle)
(b)
∠s
= 180° - 29°
= 151° (Interior angles)
(c)
∠r
= 180° - 29° - 29° - 41°
= 96° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 96°