In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 45°, ∠KLJ = 36° and ∠FJG = 113°, find
- ∠r
- ∠t
- ∠s
(a)
∠KJL = ∠FJG = 113° (Vertically opposite angles)
∠r
= 180° - 113° - 36°
= 31° (Angles sum of triangle)
(b)
∠t
= 180° - 31°
= 149° (Interior angles)
(c)
∠s
= 180° - 31° - 31° - 36°
= 99° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 99°