In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 47°, ∠KLJ = 36° and ∠FJG = 118°, find
- ∠g
- ∠i
- ∠h
(a)
∠KJL = ∠FJG = 118° (Vertically opposite angles)
∠g
= 180° - 118° - 36°
= 26° (Angles sum of triangle)
(b)
∠i
= 180° - 26°
= 154° (Interior angles)
(c)
∠h
= 180° - 26° - 26° - 36°
= 97° (Angles sum of triangle)
Answer(s): (a) 26°; (b) 154°; (c) 97°