In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 41°, ∠JKH = 32° and ∠EHF = 118°, find
- ∠b
- ∠d
- ∠c
(a)
∠JHK = ∠EHF = 118° (Vertically opposite angles)
∠b
= 180° - 118° - 32°
= 30° (Angles sum of triangle)
(b)
∠d
= 180° - 30°
= 150° (Interior angles)
(c)
∠c
= 180° - 30° - 30° - 32°
= 107° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 107°