In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 48°, ∠STR = 38° and ∠NRP = 119°, find
- ∠a
- ∠c
- ∠b
(a)
∠SRT = ∠NRP = 119° (Vertically opposite angles)
∠a
= 180° - 119° - 38°
= 23° (Angles sum of triangle)
(b)
∠c
= 180° - 23°
= 157° (Interior angles)
(c)
∠b
= 180° - 23° - 23° - 38°
= 94° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 94°