In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 42°, ∠VWU = 34° and ∠RUS = 111°, find
- ∠r
- ∠t
- ∠s
(a)
∠VUW = ∠RUS = 111° (Vertically opposite angles)
∠r
= 180° - 111° - 34°
= 35° (Angles sum of triangle)
(b)
∠t
= 180° - 35°
= 145° (Interior angles)
(c)
∠s
= 180° - 35° - 35° - 34°
= 104° (Angles sum of triangle)
Answer(s): (a) 35°; (b) 145°; (c) 104°