In the figure, NPQ is parallel to TUV and the line TQ cuts ∠PTV into half. Given that QT and PU are straight lines, ∠NPT = 50°, ∠TUS = 40° and ∠PSQ = 119°, find
- ∠v
- ∠x
- ∠w
(a)
∠TSU = ∠PSQ = 119° (Vertically opposite angles)
∠v
= 180° - 119° - 40°
= 21° (Angles sum of triangle)
(b)
∠x
= 180° - 21°
= 159° (Interior angles)
(c)
∠w
= 180° - 21° - 21° - 40°
= 90° (Angles sum of triangle)
Answer(s): (a) 21°; (b) 159°; (c) 90°