In the figure, HJK is parallel to NPQ and the line NK cuts ∠JNQ into half. Given that KN and JP are straight lines, ∠HJN = 46°, ∠NPM = 39° and ∠JMK = 118°, find
- ∠s
- ∠v
- ∠t
(a)
∠NMP = ∠JMK = 118° (Vertically opposite angles)
∠s
= 180° - 118° - 39°
= 23° (Angles sum of triangle)
(b)
∠v
= 180° - 23°
= 157° (Interior angles)
(c)
∠t
= 180° - 23° - 23° - 39°
= 95° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 95°