In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 41°, ∠JKH = 40° and ∠EHF = 117°, find
- ∠s
- ∠v
- ∠t
(a)
∠JHK = ∠EHF = 117° (Vertically opposite angles)
∠s
= 180° - 117° - 40°
= 23° (Angles sum of triangle)
(b)
∠v
= 180° - 23°
= 157° (Interior angles)
(c)
∠t
= 180° - 23° - 23° - 40°
= 99° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 99°