In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 42°, ∠LMK = 41° and ∠GKH = 112°, find
- ∠h
- ∠j
- ∠i
(a)
∠LKM = ∠GKH = 112° (Vertically opposite angles)
∠h
= 180° - 112° - 41°
= 27° (Angles sum of triangle)
(b)
∠j
= 180° - 27°
= 153° (Interior angles)
(c)
∠i
= 180° - 27° - 27° - 41°
= 97° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 97°