In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 44°, ∠LMK = 41° and ∠GKH = 110°, find
- ∠a
- ∠c
- ∠b
(a)
∠LKM = ∠GKH = 110° (Vertically opposite angles)
∠a
= 180° - 110° - 41°
= 29° (Angles sum of triangle)
(b)
∠c
= 180° - 29°
= 151° (Interior angles)
(c)
∠b
= 180° - 29° - 29° - 41°
= 95° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 95°