In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 43°, ∠JKH = 39° and ∠EHF = 118°, find
- ∠w
- ∠y
- ∠x
(a)
∠JHK = ∠EHF = 118° (Vertically opposite angles)
∠w
= 180° - 118° - 39°
= 23° (Angles sum of triangle)
(b)
∠y
= 180° - 23°
= 157° (Interior angles)
(c)
∠x
= 180° - 23° - 23° - 39°
= 98° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 98°