In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 49°, ∠LMK = 41° and ∠GKH = 114°, find
- ∠h
- ∠j
- ∠i
(a)
∠LKM = ∠GKH = 114° (Vertically opposite angles)
∠h
= 180° - 114° - 41°
= 25° (Angles sum of triangle)
(b)
∠j
= 180° - 25°
= 155° (Interior angles)
(c)
∠i
= 180° - 25° - 25° - 41°
= 90° (Angles sum of triangle)
Answer(s): (a) 25°; (b) 155°; (c) 90°