In the figure, BCD is parallel to GHJ and the line GD cuts ∠CGJ into half. Given that DG and CH are straight lines, ∠BCG = 42°, ∠GHF = 33° and ∠CFD = 113°, find
- ∠w
- ∠y
- ∠x
(a)
∠GFH = ∠CFD = 113° (Vertically opposite angles)
∠w
= 180° - 113° - 33°
= 34° (Angles sum of triangle)
(b)
∠y
= 180° - 34°
= 146° (Interior angles)
(c)
∠x
= 180° - 34° - 34° - 33°
= 105° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 146°; (c) 105°