In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 46°, ∠JKH = 36° and ∠EHF = 117°, find
- ∠e
- ∠g
- ∠f
(a)
∠JHK = ∠EHF = 117° (Vertically opposite angles)
∠e
= 180° - 117° - 36°
= 27° (Angles sum of triangle)
(b)
∠g
= 180° - 27°
= 153° (Interior angles)
(c)
∠f
= 180° - 27° - 27° - 36°
= 98° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 98°