In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 49°, ∠KLJ = 36° and ∠FJG = 114°, find
- ∠n
- ∠q
- ∠p
(a)
∠KJL = ∠FJG = 114° (Vertically opposite angles)
∠n
= 180° - 114° - 36°
= 30° (Angles sum of triangle)
(b)
∠q
= 180° - 30°
= 150° (Interior angles)
(c)
∠p
= 180° - 30° - 30° - 36°
= 95° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 95°