In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 50°, ∠VWU = 34° and ∠RUS = 115°, find
- ∠g
- ∠i
- ∠h
(a)
∠VUW = ∠RUS = 115° (Vertically opposite angles)
∠g
= 180° - 115° - 34°
= 31° (Angles sum of triangle)
(b)
∠i
= 180° - 31°
= 149° (Interior angles)
(c)
∠h
= 180° - 31° - 31° - 34°
= 96° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 96°