In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 47°, ∠WXV = 35° and ∠SVT = 115°, find
- ∠c
- ∠e
- ∠d
(a)
∠WVX = ∠SVT = 115° (Vertically opposite angles)
∠c
= 180° - 115° - 35°
= 30° (Angles sum of triangle)
(b)
∠e
= 180° - 30°
= 150° (Interior angles)
(c)
∠d
= 180° - 30° - 30° - 35°
= 98° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 98°