In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 48°, ∠JKH = 34° and ∠EHF = 119°, find
- ∠t
- ∠w
- ∠v
(a)
∠JHK = ∠EHF = 119° (Vertically opposite angles)
∠t
= 180° - 119° - 34°
= 27° (Angles sum of triangle)
(b)
∠w
= 180° - 27°
= 153° (Interior angles)
(c)
∠v
= 180° - 27° - 27° - 34°
= 98° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 98°