In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 44°, ∠JKH = 36° and ∠EHF = 120°, find
- ∠m
- ∠p
- ∠n
(a)
∠JHK = ∠EHF = 120° (Vertically opposite angles)
∠m
= 180° - 120° - 36°
= 24° (Angles sum of triangle)
(b)
∠p
= 180° - 24°
= 156° (Interior angles)
(c)
∠n
= 180° - 24° - 24° - 36°
= 100° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 100°