In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 48°, ∠LMK = 32° and ∠GKH = 110°, find
- ∠r
- ∠t
- ∠s
(a)
∠LKM = ∠GKH = 110° (Vertically opposite angles)
∠r
= 180° - 110° - 32°
= 38° (Angles sum of triangle)
(b)
∠t
= 180° - 38°
= 142° (Interior angles)
(c)
∠s
= 180° - 38° - 38° - 32°
= 100° (Angles sum of triangle)
Answer(s): (a) 38°; (b) 142°; (c) 100°