In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 42°, ∠HJG = 40° and ∠DGE = 117°, find
- ∠m
- ∠p
- ∠n
(a)
∠HGJ = ∠DGE = 117° (Vertically opposite angles)
∠m
= 180° - 117° - 40°
= 23° (Angles sum of triangle)
(b)
∠p
= 180° - 23°
= 157° (Interior angles)
(c)
∠n
= 180° - 23° - 23° - 40°
= 98° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 98°