In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 44°, ∠LMK = 34° and ∠GKH = 119°, find
- ∠a
- ∠c
- ∠b
(a)
∠LKM = ∠GKH = 119° (Vertically opposite angles)
∠a
= 180° - 119° - 34°
= 27° (Angles sum of triangle)
(b)
∠c
= 180° - 27°
= 153° (Interior angles)
(c)
∠b
= 180° - 27° - 27° - 34°
= 102° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 102°