In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 42°, ∠PQN = 34° and ∠KNL = 114°, find
- ∠t
- ∠w
- ∠v
(a)
∠PNQ = ∠KNL = 114° (Vertically opposite angles)
∠t
= 180° - 114° - 34°
= 32° (Angles sum of triangle)
(b)
∠w
= 180° - 32°
= 148° (Interior angles)
(c)
∠v
= 180° - 32° - 32° - 34°
= 104° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 104°