In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 42°, ∠STR = 33° and ∠NRP = 117°, find
- ∠s
- ∠v
- ∠t
(a)
∠SRT = ∠NRP = 117° (Vertically opposite angles)
∠s
= 180° - 117° - 33°
= 30° (Angles sum of triangle)
(b)
∠v
= 180° - 30°
= 150° (Interior angles)
(c)
∠t
= 180° - 30° - 30° - 33°
= 105° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 105°